WebSimplify (a+b-c)(a+b+c) Step 1. Expand by multiplying each term in the first expression by each term in the second expression. Step 2. Simplify terms. Tap for more steps... Step 2.1. Combine the opposite terms in . Tap for more steps... Step 2.1.1. Reorder the factors in the terms and . Step 2.1.2. Subtract from . Step 2.1.3. WebJan 14, 2013 · The numbers a, 7, b, 23, c are in AP. Let d be the common difference. 7 = a + d b = a + 2d 23 = a + 3d c = a + 4d b is the middle term between 7 and 23. d = 23 - 15 = 8 ∴a = 7 - 8 = -1 c = 23 + d = 31 18. The first number greater than 10 which when divided by 4 leaves a remainder 3 is 11. So, the next number will be 11 + 4 = 15.
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Web5 hours ago · WASHINGTON (AP) — A Massachusetts Air National Guard member was arrested Thursday in connection with the disclosure of highly classified military documents about the Ukraine war and other top ... WebApr 21, 2024 · a=-1,b=15,c=41 Step-by-step explanation: Step1: Make all the common differences They are 7-a b-7 23-b c-23 Step 2: Equate 7-a and b-7 You will get a+b value Equate 7-a and 23-b you will get a-b you will get a and b values now equate 23-b and c-23 as you already got b value now you substitute into that You will get answer Advertisement
WebAug 31, 2024 · Now, we have been given that a,7,b,23 and c are in AP. We know that if three numbers x,y and z are in AP then they have the property: \[2y=x+z\] Now, from the … Web4 hours ago · AP sources: Snyder agrees to $6.05B sale of NFL's Commanders Two people with knowledge of the situation tell The Associated Press that a group led by Josh Harris …
WebFind a, b and c such that the following numbers are in AP: a, 7, b, 23, c. Solution: For a, 7, b, 23, c… to be in AP it should satisfy the condition, a 5 - a 4 = a 4 - a 3 = a 3 - a 2 = a 2 … WebApr 4, 2024 · Now, we have been given that a,7,b,23 and c are in AP. We know that if three numbers x,y and z are in AP then they have the property: 2 y = x + z Now, from the given the series, if we take the first three numbers a,7 and b, then from the above mentioned property we will get: 2 ( 7) = a + b ⇒ 14 = a + b ……. (i)
WebFind a, b and c such that the following numbers are in AP: a, 7, b, 23, c. Solution: The below given condition needs to be satisfied for a, 7, b, 23, c… to be in AP,
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