Dataspider string index out of range: -1
WebNov 23, 2013 · 1 I am getting the following error when calling a function from within my class: java.lang.StringIndexOutOfBoundsException: String index out of range: -1 Although I used a system prints to see the inputs I am passing in the substring () function and everything seems to be right. WebThis works, because the loop starts at zero, and ends at Length-1 because index is no longer less than Length. This, however, will throw an exception: for (int index = 0; index <= array.Length; index++) { Console.WriteLine (array [index]); } Notice the <= there? index will now be out of range in the last loop iteration, because the loop thinks ...
Dataspider string index out of range: -1
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WebI am attempting what seems like a simple operation-- parsing Cisco router outputs using simple string functions (like 'split'). However, I keep getting an error that an index is out … WebSorted by: 3 Use for i in range (len (s)-1) or g!=len (s)-1 len () gives you the total number of characters, which will be the index of the character after the last one since indexing …
WebJul 20, 2024 · The error occurs because the empty string doesn't have anything at index 0. Just as "a" doesn't have anything at index >1. A little trick to avoid the error or even … WebYou can check it by print out data: for game in frame: print(game, len(game)) Pretty sure that at least one game will have less than 4 characters inside. E.g. pyt, so when you call …
WebDec 13, 2016 · You see, all these methods such as indexOf (), or lastIndexOf () return -1 when there is no such index. In other words: before processing your strings and using "indexes" for substring calls ... you have to validate your assumptions about the layout of your incoming string! For example by doing things like WebOct 18, 2016 · String Index out of range Exception in jdbc programming. I have a database table consisting of 6 columns and 6 rows. I want to access all 6 column values of the 2nd …
WebJun 2, 2012 · When indexOf () returns -1, it means that the value couldn't be found in the String. So, in this case, you're searching a String for '.' which doesn't exist in the String. …
WebApr 27, 2014 · Two solutions - one naive, one slightly better than naive - either use a String [] or a Map to hold your data. Here's a solution using a Map: Map statData = new HashMap<> (); statData.put ("Health", "433 (+78)"); statData.put ("Attack damage", "52.3 (+3.9)"); // and so forth Share Improve this answer Follow trump zoom backgroundWebJul 13, 2010 · The string abcde has index start from 0 to 4, but the substring () method takes startIndex and endIndex as arguments based on the fact that I can call foo.substring (0) and get "abcde". Then why does substring (5) work? That index should be out of range. What is the explanation? philippines memorialWebMar 9, 2016 · Cause: org.apache.ibatis.type.TypeException: Error setting non null for parameter #1 with JdbcType VARCHAR . Try setting a different JdbcType for this parameter or a different configuration property. Cause: java.sql.SQLException: Parameter index out of range (1 > number of parameters, which is 0). trumsubthegioiWebMay 29, 2012 · String().indexOf will return -1 if there is no match. String().substring will throw an StringIndexOutOfBoundsException if you give it a negative begin value. This is all documented at http://docs.oracle.com/javase/1.5.0/docs/api/java/lang/String.html. Thus, … philippines mental health actWebif guess in word: print ("\nYes!", guess, "is in the word!") # Create a new variable (so_far) to contain the guess new = "" i = 0 for i in range (len (word)): if guess == word [i]: new += … trum son high schoolWebGive me the light! :D. java.lang.StringIndexOutOfBoundsException: String index out of range: 13113 at java.lang.String.checkBounds (String.java:401) at java.lang.String. … philippines memorial parkWebSorted by: 3 Use for i in range (len (s)-1) or g!=len (s)-1 len () gives you the total number of characters, which will be the index of the character after the last one since indexing starts at 0. You can get rid of the if g!=0 and g!=len (s) part all together if you use for i in range (1,len (s)-1) Share Improve this answer Follow trum speed test